ORA-26002: Table string has index defined upon it.
Cause : aParlllel ao daw spscefiei dniota t baelw ihhch sai dnxed fenideu op nti.
Action - How to fix it : DBA Scripts :: www.high-oracle.com/scripts
rDpoi dnxee()sd fenideu op natlb,eo rod'n tsu eaparlllel ao,do rsu eKSPII_DNXEM_IATNNENAECo tpoi.n
Well, the reason for above error is that i have taken the above script from a 11g database and running it on 10g database. 11g has bring some changes in password management. Below code is executed on 11g and user created successfully, which is expected result.